BCR405U apr-27-2004 1 led driver ? supplies stable bias current even at low battery voltage ? ideal for stabilizing bias current of leds ? negative temperature coefficient protects leds against thermal overload ? suitable for 12v automotive applications vpw09197 1 2 3 4 5 6 type marking pin configuration package BCR405U l5s 1 = gnd 2;3;5 = i ou t 4 = v s 6 = r ext sc74 maximum ratings parameter symbol value unit source voltage v s 40 v output current v s = 10 v i out 65 ma output voltage v out 38 v reverse voltage between all terminals v r 0.5 total power dissipation , t s = 117 c p tot 500 mw junction temperature t j 150 c storage temperature t stg -65 ... 150 thermal resistance parameter symbol value unit junction - soldering point 1) r thjs 50 k/w 1 for calculation of r thja please refer to application note thermal resistance
BCR405U apr-27-2004 2 electrical characteristics at t a =25c, unless otherwise specified parameter symbol values unit min. typ. max. characteristics supply current v s = 10 v i s - 500 900 a output current v s = 10 v i out 45 50 55 ma dc characteristics with stabilized led load lowest sufficient battery voltage overhead i out > 18ma v smin - 1.4 - v voltage drop (v s - v ce ) i out = 20 ma v drop - 0.8 - output current change versus t a v s = 10 v ? i out / i out - -0.15 - %/k output current change versus v s v s = 10 v ? i out / i out - 1 - %/v
BCR405U apr-27-2004 3 total power dissipation p tot = f ( t s ) 0 20 40 60 80 100 120 c 150 t s 0 0.4 0.8 1.2 1.6 2 2.4 w 3.2 p tot permissible pulse load r thjs = f ( t p ) 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p -1 10 0 10 1 10 2 10 3 10 k/w r thjs 0.5 0.2 0.1 0.05 0.02 0.01 0.005 d = 0 permissible pulse load p totmax / p totdc = f ( t p ) 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p 0 10 1 10 2 10 3 10 - p totmax / p totdc d = 0 0.005 0.01 0.02 0.05 0.1 0.2 0.5
BCR405U apr-27-2004 4 output current versus supply voltage i out = f ( v s ); r ext = parameter v s - v out = 1.4 v 0 5 10 15 20 25 30 35 v 45 v s -2 10 -1 10 a i out 56 ohm 82 ohm open supply current versus supply voltage i s = f ( v s ) t a = parameter 0 5 10 15 20 25 30 35 40 v 50 v s 0 0.0002 0.0004 0.0006 0.0008 0.001 0.0012 0.0014 0.0016 a 0.002 i s 80c 20c -40c output current versus supply voltage i out = ? ( v s ), t a = 20c v s - v out as parameter 0 5 10 15 20 25 30 35 v 45 v s -2 10 -1 10 a i out 1 v 1.2v - 2v output current versus supply voltage i out = ? ( v s ), v s - v out = 1.4 v t a = parameter 0 5 10 15 20 25 30 35 v 45 v s -2 10 -1 10 a i out -40c 20c 80c
BCR405U apr-27-2004 5 output current versus external resistor i out = ( r ext ), v s = 10v, v s - v out = 1.4 v t a = parameter 10 1 10 2 r ext -2 10 -1 10 a i out -40c 20c 80c application circuit:
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